Math, asked by mastermind100is1, 2 months ago


7. The number of consecutive zeroes in
2^3 x 5^4 x 3^4 x 7 is​

Answers

Answered by ayesha7734
1

Answer:

We take the minimum number of 2s and 5s [Logically and theoretically too]. So, the number of zeros in X will be 3. In your question, there are three 2s and four 5s. Since there are only three 2s, there will be only one three consecutive zeros.

Step-by-step explanation:

hope it is helpful for you

Answered by mrperfect0240
0

Answer:

3

Step-by-step explanation:

2^3 x 5^4 x 3^4 x 7 can be written as 2x2x2x5x5x5x5x3x3x3x3x7, this can be simplified to 2x5x2x5x2x5x5x3x3x3x3x7. 2x5 = 10, so there such 3 pairs so there would be 3 consecutive zeros. Well if you multiply you would get 2835000  

Similar questions