7. The number of consecutive zeroes in
2^3 x 5^4 x 3^4 x 7 is
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Answered by
1
Answer:
We take the minimum number of 2s and 5s [Logically and theoretically too]. So, the number of zeros in X will be 3. In your question, there are three 2s and four 5s. Since there are only three 2s, there will be only one three consecutive zeros.
Step-by-step explanation:
hope it is helpful for you
Answered by
0
Answer:
3
Step-by-step explanation:
2^3 x 5^4 x 3^4 x 7 can be written as 2x2x2x5x5x5x5x3x3x3x3x7, this can be simplified to 2x5x2x5x2x5x5x3x3x3x3x7. 2x5 = 10, so there such 3 pairs so there would be 3 consecutive zeros. Well if you multiply you would get 2835000
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