7. The number of water moleculars present in a drop of water weighing 0.05 mg is
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Answer:
hello!!
Step-by-step explanation:
No. of molecules= (Given mass/Molecular mass)× Avogadro number
(0.05÷18)×6.023×10²³
=1.672×10²² molecules,ie
=16720000000000000000000 molecules
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