Question

7. The perimeter of a parallelogram is 140 cm. If one of the sides is longer than the other by
10 cm, find the length of each of its sides.​

Answer 1

Answer:

Let the length of one side be x.

Then other side is 10 more=x+10

ATF,

perimeter of a parralelogram=2(l+b)

.: 2 (x+(x+10))=140

2 (x+x+10)=140

2 (2x+10)=140

(2x+10)=140/2

(2x+10)=70

(2x)=70-10

2x=60

x=30.....

.: one of the side of parralelogram=x=30cm. another side of the parralelogram=(x+10)=40cm.

HOPE THIS WILL HELP YOU:)

Answer 2

$\sf{\bold{\green{\underline{\underline{Given}}}}}$

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• perimeter of a parallelogram is 140cm.
• One side is longer then the other by 10cm

$\sf{\bold{\green{\underline{\underline{To\: Find }}}}}$

• Length and Breadth = ??

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$\sf{\bold{\green{\underline{\underline{Solution}}}}}$

Let the length of parallelogram be = x cm

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Let the Breadth of parallelogram be = x + 10 cm

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$\sf{\red{\boxed{\bold{Perimeter = 2 ( length + breadth ) }}}}$

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According to the question :-

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140 = 2(x + x + 10)

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140 = 2x + 2x + 20

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140 = 4x + 20

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4x = 140 - 20

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4x = 120

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x = 120/4

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x = 30

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Length = x

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⟹ 30cm

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Breadth = x + 10

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⟹ 30 + 10

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⟹ 40 cm

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$\sf{\bold{\green{\underline{\underline{Answer}}}}}$

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• Length = 30cm
• Breadth = 40cm

$\sf{\red{\boxed{\bold{Extra\: info :- }}}}$

• Area of parallelogram = base × height
• perimeter = 2 (l + b)