Question

7) The perimeter of a parallelogram is 68m. If the ratio of two sides of parallelogram is 7:10, find lengths of sides of parallelogram​

Answer 1

Answer:

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Step-by-step explanation:

$so \: here \: for \: a \: particular \: parallelogram \\ ratio \: of \: its \: two \: sides = 7 \div 10$

$so \: let \: the \: common \: multiple \: be \: k \\ thus \: then \: its \: side = 7k \\ base = 10k$

$so \: we \: know \: that \\ perimeter \: of \: parallelo gram = 2(side+ base)$

$so \: here \: perimeter \: of \: parallelogram = 68 \: cm \\ thus \: then \\ 68 = 2(10k + 7k) \\ = 2 \times 17k \\ 68= 34k \\ ie \: k = 2$

$so \: substituting \: value \: of \: k \: in \: missing \: terms \\ we \: get \\ 7k = (7 \times 2) \\ = 14cm \\ \\ \\ also \: similarly \\ 10k = (10 \times 2) \\ = 20cm$

$hence \: sides \: of \: paallelogram \: are \: 14cm \: and \: 20cm$