Question

7. The perimeter of a rectangle is 130 cm. If the breadth of the 30 cm, find its length. Also find the area of the rectangle Tectan​

Answer 1

Answer:

2(l+b) = perimeter

130/2= 65

65-30= 35 = length

area = lxb

35x30 = 1050cm²

Answer 2

Answer:

Given :-

• The perimeter of a rectangle is 130 cm.
• The breadth of rectangle is 30 cm.

To Find :-

• What is the length and area of the rectangle.

Formula Used :-

$\clubsuit$ Perimeter Of Rectangle Formula :

$\small \bigstar \: \: \: \: \sf\boxed{\bold{\pink{Perimeter_{(Rectangle)} =\: 2(Length + Breadth)}}}\: \: \: \: \bigstar$

$\clubsuit$ Area Of Rectangle Formula :

$\small \bigstar \: \: \: \: \sf\boxed{\bold{\pink{Area_{(Rectangle)} =\: Length \times Breadth}}}\: \: \: \: \bigstar$

Solution :-

First, we have to find the length of a rectangle :

Let,

$\mapsto \bf Length_{(Rectangle)} =\: x\: cm$

Given :

• Perimeter of Rectangle = 130 cm
• Breadth of Rectangle = 30 cm

According to the question by using the formula we get,

$\implies \sf 130 =\: 2(x + 30)$

$\implies \sf 130 =\: 2x + 60$

$\implies \sf 130 - 60 =\: 2x$

$\implies \sf 70 =\: 2x$

$\implies \sf \dfrac{70}{2} =\: x$

$\implies \sf\bold{\red{x =\: 35\: cm}}$

Hence, the length of the rectangle is 35 cm .

Now, we have to find the area of a rectangle :

Given :

• Length of Rectangle = 35 cm
• Breadth of Rectangle = 30 cm

According to the question by using the formula we get,

$\mapsto \sf Area_{(Rectangle)} =\: 35 \times 30$

$\mapsto \sf\bold{\red{Area_{(Rectangle)} =\: 1050\: cm^2}}$

Hence, the area of the rectangle is 1050 cm² .

$\therefore$ The length of the rectangle is 35 cm and the area of the rectangle is 1050 cm² .