Question

7. The population of a city was 62500 on the last day
of the year 2001. During the next two years, it
increased by 4% but in the year 2004, there was a
decrease in the population by 10% due to an
epidemic. Find its population at the end of the
year 2004.​

Answer 1

Answer:

A=p(1+r/100)²(1-r/100)

=62500(1+4/100)²(1-10/100)

=62500(1+1/25)²(1-1/10)

=62500(26/25)²(9/10)

=62500×(676/625)(9/10)

=100×676×9/10

=10×676×9

=60840

hence at the end of 2004 population will be 60840

.....666.....