7. The population of a town increases 10% every
3 years. If the present population of the town is
72.600, calculate
(1) its population after 6 years,
(11) its population 6 years ago.
Answers
Step-by-step explanation:
Present population of town = 72,600
Population increases by 10% every 3 years
Population after 3 years= 72,600 + 10% of 72,600
= 72,600 + 7,260
= 79,860
Population after 6 years =79,860 + 10% of 79,860
= 79,860 + 7,986
=87,846
(ii) Let population 6 years ago = 100
Then population 3 years ago = 100 + 10% of 100
= 100 + 10
= 110
And present population = 110 + 10% of 110
= 110 + 11
= 121
When present population is 121, population 6 years ago= 100
When present population is 72,600, population 6 years ago