Question

7. The ratio of kinetic energy to potential enero
electron of H-atom is
(1) 1:2
(2) - 1:2
(3) 1:1
(4) -1:1
​

Answer 1

Solution :

⏭ To Find :

✏ The ratio of kinetic energy to potential energy for electron of hydrogen atom.

⏭ Formula :

✏ Formula of kinetic energy for electron of hydrogen atom is given by

$\star \: \boxed{ \sf{ \pink{KE= \frac{1}{2} m {v}^{2} = \frac{1}{2} \frac{Z {e}^{2} }{r}}}} \: \star$

✏ Formula of potential energy for electron of hydrogen atom is given by

$\star \: \boxed{ \sf{ \purple{PE = - \frac{Z {e}^{2} }{r} }}} \: \star$

⏭ Terms indication :

✏ Z denotes atomic number

✏ e denotes charge

✏ r denotes radius of orbit

⏭ Calculation :

$\rightarrow \sf \: \frac{KE}{PE} = \frac{1}{2} \frac{Z {e}^{2} }{r} \times( - \frac{r}{Z {e}^{2} } ) \\ \\ \rightarrow \boxed{ \bold{ \sf{ \orange{KE : PE = - 1 : 2}}}} \: \red{ \bigstar}$