Question

7 The ratio of the present ages of A and B is 5:6. The ratio of their 5. before years ages was 4:5. Find their persent ages . S​

Answer 1

Answer:

let the age of A be 5 x

The ages of

′

2

′

persons are in the ratio 5:7

1st person age = 5x

2nd person age = 7x

′

18

′

years ago their ratio 8:13

7x−18

5x−18

=

13

8

13(5x−18)=8(7x−18)

65x−234=56x−144

65x−56x=234−144

9x=90

x=10

1st person age = 5×10=50yrs

2nd person age = 7×10=70yrs

Step-by-step explanation:

Hope it is helpful

Answer 2

Step-by-step explanation:

Let the present age of A be x

Let the present age of B be y

$\frac{x}{y} = \frac{5}{6}$

Also ratio five years ago,

$\frac{x - 5}{y - 5} = \frac{4}{5}$

$\frac{6x}{5} = y$

Using y = 6x/5 in equation 2,

$5x - 25 = 4y - 20$

$5x - 25 = \frac{24x}{5} - 20$

$\frac{25x}{5} - \frac{24x}{5} = 5$

$\frac{x}{5} = 5$

$x = 25$

Using x=25 in equation 1

y = 30