Question

7. The roots of (x2 - 3x + 2) (x) (x - 4) = 0 are:
(a) 4
(b) 0 and 4
(c) 1 and 2
(d) 0, 1, 2 and 4
(e) 1, 2 and 4
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Answer 1

Answer:

option d is the correct Mark my answer as brainliast

Answer 2

$\bf⚝\:AnSwEr\:⚝$

$\begin{gathered} \sf ➣\: (x {}^{2} - 3x + 2)(x)(x - 4) \\ \sf➣\: (x { }^{2} - 2x - x + 2)(x)(x - 4) \\\sf ➣\:x(x - 2) - 1(x - 2)(x)(x - 4) \\\sf ➣\:( x - 1)(x - 2)(x)(x - 4) \\\sf ➣\: x = 1 \\\sf ➣\:x = 2 \\\sf ➣\: x = 4 \\\sf ➣\: x = 0\end{gathered}$

Solving

$\sf ⤖ x^2-3x-4 = 0$ directly

• Earlier we factored this polynomial by splitting the middle term. let us now solve the equation by Completing The Square and by using the Quadratic Formula

Parabola, Finding the Vertex:

Find the Vertex of

$\sf ⟿\:y = x^2-3x-4$

• Parabolas have a highest or a lowest point called the Vertex . Our parabola opens up and accordingly has a lowest point (AKA absolute minimum) . We know this even before plotting "y" because the coefficient of the first term, 1 , is positive (greater than zero).