Question

7. The sides of a right angled triangle are in A.P. Show that they are in the ratio 3:4:5.
8. For what value of k will k + 9, 2k – 1 and 2k + 7 are the consecutive terms of an A.P. [C
[Hint. a, b, c are three consecutive terms in an A.P. if b - a=c-b

The sides of a right angled triangle are in A.P. Show that they are in the ratio 3:4:5.

Answer 1

Step-by-step explanation:

Let k+9=a

2k−1=b

2k+7=c

To be in AP,

a+c=2b

k+9+2k+7=2(2k−1)

⇒ 3k+16=4k−2

⇒ 3k−4k=−2−16

⇒ −k=−18

∴k=18

For k=18, the terms k+9,2k−1,2k+7 are in A.P