Question

7. The sum of the areas of two squares is
640 m2. If the difference between their
perimeters is 64m, then find sides of the
square.​

Answer 1

Answer:

Let side of first square be x and that of another be y

Ist case

area of square = (side)2

x2 + y2 =640 -------------------------- (i)

2nd case

4x -4y =64

-> x-y=16

x=16+y

put value of x in 1

(16+y)2+y2=640

256+y2+32y+y2 =640

2y2 +32y =384

y2+16y=192

y2 + 24y-8y -192=0

y(y+24) -8(y+24)=0

y=8

and x=24

hope u get it

thank you