7. The sum of three consecutive integers is 48. Find the three integers.
Answers
Answered by
4
Step-by-step explanation:
Let the three consecutive integers =
x, x+1,x+2
Given: x+x+1+x+2 =48
=> 3x+3=48
=> 3x = 45
=> x = 45/3
x = 15
The three consecutive numbers are:
x = 15
x + 1 = 16
x + 2 = 17
CHECK:
15 + 16 + 17 = 48
Hope it helps:)
Answered by
0
Let the numbers be x, (x + 1) and (x + 2)
x + (x + 1) + (x + 2) = 48
3x + 3 = 48
3x = 48 - 3
3x = 45
x = 45/3
x = 15
So, the first number is 15
For finding 2nd and 3rd number
15 + 1
= 16
15 + 2
= 17
So, the second number is 16
And the third number is 17
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