Question

7. The sum of three consecutive integers is 48. Find the three integers.​

Answer 1

Step-by-step explanation:

Let the three consecutive integers =

x, x+1,x+2

Given: x+x+1+x+2 =48

=> 3x+3=48

=> 3x = 45

=> x = 45/3

x = 15

The three consecutive numbers are:

x = 15

x + 1 = 16

x + 2 = 17

CHECK:

15 + 16 + 17 = 48

Hope it helps:)

Answer 2

Let the numbers be x, (x + 1) and (x + 2)

x + (x + 1) + (x + 2) = 48

3x + 3 = 48

3x = 48 - 3

3x = 45

x = 45/3

x = 15

So, the first number is 15

For finding 2nd and 3rd number

15 + 1

= 16

15 + 2

= 17

So, the second number is 16

And the third number is 17