7. The sum of three numbers in AP is 3 and their product is -35. Find the numbers
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Answer:
the no. are 7 , 1 , -5 or -5 , 1 , 7 .
Step-by-step explanation:
let one number = x
second no. = x + d
third no. = x + 2d
the sum = x + x + d + x+ 2d = 3
= 3x + 3d = 3
= 3(x + d) = 3
=x+d = 1
the product is = (x) (x+d) (x+2d) = -35
=x * (1+d) = -35
= d= -35/x - 1
put it in the first equation
x+d= 1
x + -35/x - 1 = 1
x + -35/x = 2
x^2-35= 2x
x^2-2x-35 =0
x= 7 , -5
first substiutute the value in first equation
x+d = 1
7 + d = 1
d= -6
or
x+d = 1
-5 + d = 1
d=6
the no. are 7 , 1 , -5 or -5 , 1 , 7
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