7. There are 3 red and 4 white balls in a box. Four balls are selected at random with replacement from the box. Find the probability of the event of getting (1) 2 red balls and 2 white balls (ii) all four white balls among the selected balls using binomial distribution.
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0
Answer:
I think So 2 option (ii) all four white balls among the selected balls using binomial distribution.
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1
Answer:
We have, 4 red, 2 white and 4 black balls
∴ Total balls =4+2+4=10
Number of ways of selecting 4 balls from 10 balls =
10
C
4
∴n(S)=
10
C
4
Let E = Event getting 2 red balls
∴ Required probability =p(E)
=
n(S)
n(E)
=
10
C
4
4
C
2
×
6
C
2
=
4×3×2×1
10×9×8×7
2×1
4×3
×
2×1
6×5
=
10×3×7
6×15
=
7
3
=
21
9
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