Math, asked by Anonymous, 1 year ago

7 thieves steal some Diamonds. 2 of the thieves swindle with others and divide the diamonds between each other in 2 equal parts but one Diamond remains left. Then they call one more thief in their swindle and again divide the diamonds in three equal parts but still 1 Diamond remains left.They call every thief one by one and divide those Diamonds but in every situation 1 Diamond remains left but when they call the 7th and the last thief and divide the Diamonds in 7 equal parts then all diamonds allocated equally. Not a single Diamond remains left. Then find the number of Diamonds. Give a proper solution.

Answers

Answered by sukhmani542580
2

Answer:

there are 7diamonds.......


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sukhmani542580: what happened
sukhmani542580: bro
HandsomeYaar: ya you can leave but please don't call me bro
HandsomeYaar: I hate this word
sukhmani542580: oookkkk
HandsomeYaar: yes
Anonymous: Kyo ld rhe ho bhai.
Anonymous: This answer is wrong mam.
sukhmani542580: ooookkkkk
Answered by beingSaRcAsTiC
0

Answer:

TOTAL NO. OF DIAMONDS ARE 7

Step-by-step explanation:

AS IT IS A PRIME NO. AND CANNOT BE EQUALLY DIVIDED UNTIL DIVIDED1 TO EACH AS PRIME NOS. R DIVISIBLE BY 1 OR THE NO. ITSELF......HOPE HELPS...


Anonymous: Sorry to say this mam but your answer is wrong.
Anonymous: Suppose, when they call 4th thief and divide diamonds in 4 equal parts then according to question, only one diamond should left.
sukhmani542580: oookkk
Anonymous: But if the number of Diamonds are 7 then the remaining Diamonds are 3 on dividing them in 4 equal parts.
Anonymous: ISKA MTLB AP QUESTION KO CHALLENGE KR RHI HAIN.
sukhmani542580: nahi
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