Question

7. Three numbers are in the ratio 2:4:6. If their
sum is 600, find the numbers.​

Answer 1

$\huge \star \; \bf \underbrace {ANSWER} \: \star$

‣ Given :

$\rightarrow \textsf {Three numbers are in the ratio 2:4:6}$

$\rightarrow \textsf {Thier sum is 600.}$

‣ To Find :

$\textsf {The numbers}$

‣ Solution :

$\textsf {Let the number be x.}$

$\textsf {Then,}$

$\rightarrow \sf {2x + 4x + 6x = 600}$

$\rightarrow \sf {12x = 600}$

$\rightarrow \sf {x = \frac{600}{12}}$

$\rightarrow \sf {x = 50}$

$\implies \textsf {\underline {\underline {Hence, the numbers are :-}}}$

$\longrightarrow \sf {2x = 2 × 50 = 100}$

$\longrightarrow \sf {4x = 4 × 50 = 200}$

$\longrightarrow \sf {6x = 6 × 50 = 300}$

‣ Verification :

$\textsf {Their sum :-}$

$\rightarrow \sf {100 + 200 + 300 =600}$

$\longrightarrow \sf {\underline {Hence, \: Verified}!}$

Answer 2

Given:

Three number are in the ratio 2:4:6. The sum of these three numbers is 600.

To Find:

The numbers.

Solution:

Let the number be x.

So,

The equation will be:

$\qquad : \implies \sf 2x + 4x + 6x = 200$

$\qquad : \implies \sf 12x = 600$

$\qquad : \implies \sf x = \dfrac {600}{12}$

$\qquad : \implies \bf x = 50$

Now,

$\quad : \implies \sf 2x , \ 4x \ and \ 6x$

Put the value of x in the above numbers.

$: \implies \sf 2x = 2 \times 50 = 100$

$: \implies \sf 4x = 4 \times 50 = 200$

$: \implies \sf 6x = 6 \times 50 = 300$

Therefore,

The numbers are:

• 100
• 200
• 300

Now,

The sum of numbers = ?

$\qquad : \implies \sf 100 + 200 + 300$

$\qquad : \implies \sf 600$