Question

7. Three resistance 14.5 ohm,25.5 ohm and 60 ohm are connected in series across 200 V. What
will be the voltage drop across 14.5 ohm
O A. 29 V
OB. 13.5 V
O C. 14 V
O D. 18 V

Answer 1

Answer:

A is the correct answer

Answer 2

Three resistors of resistance 14.5 ohm, 25.5 ohm and 60 ohm are connected in series across 200V.

We have to find the voltage drop across 14.5 ohm.

Take R1 = 14.5 ohm, R2 = 25.5 ohm and R3 = 60 ohm

As R1, R2 and R3 are connected in series. As shown:

-------| R1 |------| R2 |------| R3 |--------

For series combination:

Rs = R1 + R2 + R3

Substitute the known values in the above formula,

→ Rs = (14.5 + 25.5 + 60) ohm

→ Rs = 100 ohm

Now, from ohm's law we can say that,

V = IR

We have, V = 200V and R = 100 ohm So,

→ 200 = I × 100

→ 2 = I (Current = 2 A)

As per given condition we have to find the voltage drop across 14.5 ohm resistor.

V = IR

Substitute I = 2A and R = 14.5 ohm

→ V = 2(14.5)

→ V = 29 V

Therefore, the voltage drop across 14.5 ohm resistor is 29V.