Question

7. Through a rectangular field of length 90 m and breadth 60 m, two roads are
constructed which are parallel to the sides and cut each other at right angles through
the centre of the fields. If the width of each road is 3 m, find
(i) the area covered by the roads.
(ii) the cost of constructing the roads at the rate of 110 per
m.​

Answer 1

Step-by-step explanation:

Answer:-

To answer this question, let me make the figure.

Now, we can easily solve the question, with a quick catch located in the middle part.

$\boxed{\rm{Rectangular \ Area = Length \times Breadth}}$

So,

• Length is 90 m
• Breadth is 60 m

$\rm{Area = 90 \times 60}$

$\rm{Area = 5400 \ m^2}$

Calculating area of R1 now,

$\rm{Area = 3 \times 60}$

$\rm{Area = 180 \ m^2}$

Now, calculating area of R2,

$\rm{Area = 3 \times 90}$

$\rm{Area = 270 \ m^2}$

Catch Point:-

The middle area of both road is common in both. So, we will calculate that area, and subtract from any one road.

Area of Square = (side)²

= 3 × 3

= 9 m².

Now, subtracting 9 from 270, 261 cm² is the remains.

Now, (i) Area of Roads is 261 + 180 = 441 m²

(ii) the cost of constructing the roads at the rate of 110 per m²

This will be for 1 metre square. So, for 441, it will be

441 × 110

= Rs. 48510

Answer 2

Answer:

this is your answer............