7. Through a rectangular field of length 90 m and breadth 60 m, two roads are
constructed which are parallel to the sides and cut each other at right angles through
the centre of the fields. If the width of each road is 3 m, find
(i) the area covered by the roads.
(ii) the cost of constructing the roads at the rate of 110 per
m.
Answers
Answer:
Solution 7:
Length of the road along the length of the field= 90m
Breadth= 3m
Area of the road= l\times bl×b
=90m\times3m=270m^2=90m×3m=270m
2
Similarly, the area of the road parallel to the breadth of the field= l\times bl×b
=60m\times3m=180m^2=60m×3m=180m
2
Area of the common portion= 3m\times3m=9m^23m×3m=9m
2
(i) Area of the two roads
=270m^2+180m^2-9m^2=270m
2
+180m
2
−9m
2
=450m^2-9m^2=441m^2=450m
2
−9m
2
=441m
2
(ii) Cost of constructing the roads
=Rs\ 110\times441=Rs\ 48,510=Rs 110×441=Rs 48,510
Given:-
Length of Rectangular field = 90m
Breadth of Rectangular field = 60m
Width of road at centre = 3m
Need To Find:-
Area of Roads
cost of constructing the roads at the rate of ₹110 per m²
Where:-
L denotes Length
B denotes Breadth
Explanation:-
[Take a look at Attachment] In this Question, We are provided with the length of Rectangular field that is 90m and Breadth that is 60m and there is small road at centre of Rectangular field of 3m that is cuts at right angles through centre of fields.
Solution:-
PQ = 3m ; QR = 60m
EF = 90m ; FG = 3m
KL = 3m
⠀⠀
Area of Rectangular Road = QR × PQ
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 60 × 3
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 180m²
Hence, Area of Rectangular road is 180m2
∴Hence,AreaofRectangularroadis180m2
⠀⠀
_____________________________________
Now, We have to find the area Rectangular road EFGH.
Area of Rectangular road EFGH = L × B
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ = 90 × 3
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 270m²
Hence, Area of Rectangular road is 270m^2
∴Hence,AreaofRectangularroadis270m2
