7 times a two digit number is equal to 4 times the digit number obtained by reversing the order of digit if the difference of the digit is 3 find the number
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let unit place be x
tenth place be y
therefore number be 10y+x
given x-y = 3 -------(1)
also
7 ( 10y+x ) = 4 ( 10 x + y)
70y + 7x = 40x + 4y
40x - 7x = 70y - 4y
33x = 66y
x = 2y
putting this value in eq 1
2y - y = 3
y = 3
x =6
so the number is 36
tenth place be y
therefore number be 10y+x
given x-y = 3 -------(1)
also
7 ( 10y+x ) = 4 ( 10 x + y)
70y + 7x = 40x + 4y
40x - 7x = 70y - 4y
33x = 66y
x = 2y
putting this value in eq 1
2y - y = 3
y = 3
x =6
so the number is 36
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