7 times a two digit number is equal to 4 times the number obtained by reversing the order of its digits if the difference of the digits is 3 determine the number
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let the 2 digit no. be 10x + y.
a/q, 7(10x+y) = 4(10y+x)
70x + 7y = 40 y + 4x
70x - 4x = 40y - 7y
66x = 33y
2x = y
2(y-3) = y
2y - 6 = y
y = 6
the no. is 36
a/q, 7(10x+y) = 4(10y+x)
70x + 7y = 40 y + 4x
70x - 4x = 40y - 7y
66x = 33y
2x = y
2(y-3) = y
2y - 6 = y
y = 6
the no. is 36
nandana12:
Is this crt
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hope this is correct and would help you.
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