Question

7. trangleABC is an equilateral triangle. Point P is on base BC such that PC 1/3BC, if AB = 6 cm,find AP.​

Answer 1

Answer:

△ABC is an equilateral triangle. Point P is on base BC.     [ Given ]

PC=31BC,AB=6cm                                [ Given ]

Here, PC=31×BC=31×6

∴  PC=2cm

RC=21×BC=21×6

∴   RC=3cm

RP=RC−PC=3−2

∴   RP=1cm                 ------ ( 1 )

⇒  Altitude AR=23×a                 [ a=length of side ]

⇒  AR=23×6=33

Now, in △ARP,

(AP)2=(AR)2+(RB)2

AP=(33)2+(1)

Step-by-step explanation:

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