Physics, asked by rajnikantdubey256, 1 year ago

7.Two blocks of masses 8kg and 6kg are connected with a string & placed on a rough horizontal surface.Surface itself is accelerating up with 2 m/s2. Two forces 60 N each are acting on the two blocks asshown. Friction coefficient for 8kg is 0.5 & that for 6 kg is 0.6. Tension in the string is : (g = 10 m/s"GON60NВkg6kg2m/su=0.5(1) 60 N(2) 12 N=0.6(3) 43.2 N(4) 16.8 N​

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Answered by Anonymous
1

fR for 8 kg = 0.5 × 8(10 + 2) = 48 N fR for 6 kg = 0.6 × 6 (10 + 2) = 43.2 N It can be verified that limiting friction will act on 6 kg From FBD, tension = 16.8 N

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