7) Two bodies at rest explodes into two fragments at a height 'h' and moves
horizontally opposite direction from the same height (or) a bomb at rest explodes
into two fragments at a height h and moves horizontally in opposite directions
with velocities u, and u, respectively then
Answers
Answer:
Initial Momentum of the system is zero.
So just after the blast momentum of the system will be zero hence particle will move in the opposite direction
such that
M
1
V
1
=M
2
V
2
because M
1
=M
2
hence V
1
=V
2
So when their velocity vectors are perpendicular to each other then dot product of their velocity will be zero
hence
(−10
i
^
−gt
j
^
).(10
i
^
−gt
j
^
)=0
hence
t=
g
10×10
=1sec
Explanation:
Initial Momentum of the system is zero.
So just after the blast momentum of the system will be zero hence particle will move in the opposite direction
such that
M
1
V
1
=M
2
V
2
because M
1
=M
2
hence V
1
=V
2
So when their velocity vectors are perpendicular to each other then dot product of their velocity will be zero
hence
(−10
i
^
−gt
j
^
).(10
i
^
−gt
j
^
)=0
hence
t=
g
10×10
=1sec