Physics, asked by nkhanhhuyen2k1, 11 hours ago

7. Two bunnies hop at slightly different rates but remain side by side. The first takes 50 hops per minute and the other takes 48 hops per minute. If they begin hopping together, when will they again be “in step”?

Answers

Answered by Anshgamer439
1

Answer:

1200 will in 48in in 48 multiply by 27

1200will in 50 is 50 multiply by 24

Answered by GulabLachman
0

Given: Two bunnies hop at slightly different rates but remain side by side. The first takes 50 hops per minute and the other takes 48 hops per minute.

To find: If they begin hopping together, when will they again be “in step”

Explanation: The first bunny takes 50 hops per minute. Similarly it takes 100 minutes in 2 minutes.

It forms an arithmetic progression with first term 50 and common difference 50.

The expression for nth term of the A.P is:

a + (n-1) d

= 50 + (n-1) 50

= 50 + 50 n-50

= 50 n

The second bunny takes 48 hops per minute. Similarly it takes 96 minutes in 2 minutes.

It forms an arithmetic progression with first term 48 and common difference 48.

The expression for mth term of the A.P is:

a + (m-1) d

= 48 + (m-1) 48

= 48 + 48 m -48

= 48 m

Since it is asked the time when they hop in together, we equate the nth term of the first A.P to mth term of second A.P.

50 n = 48m

=> m/n = 50/48

= 25/24

=> 24 m = 25 n

This means that 25 such intervals of second bunny is equal to 24 such intervals of bunny A.

Verifying,

After 25 intervals of bunny B,

Number of hops

= 25*48

= 1200

After 24 intervals of bunny A,

Number of hops

= 24*50

= 1200

Therefore, they will step in together at the 1200th hop if they start together.

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