Question

7)Two coins are tossed simultaneously. Find the probability of getting
i)at least one head
ii)at most two heads
8)A die is thrown. Find the probability of getting
i)a prime number
ii)a composite number
iii)a number not greater than 6.
9) The total number of possible outcomes when two dice are thrown
simultaneously is ………………..
10) The probability of getting 7 in throwing a die once is ……….
11) The probability of an event E is 5/4. State True/False.

Answer 1

Step-by-step explanation:

7) P(E) = Number of favorable outcome

Total number of possible outcomes

-->Total outcomes = 4

HH

HT

TH

TT

i) S = (HH, HT, TH)

P(E) = 3/4

ii) S = (HH, HT, TH, TT)

P(E) = 4/4 = 1

8) Total outcomes --> (1, 2, 3, 4, 5, 6) = 6

i) S = ( 2, 3, 5)

P(E) = 3/6 = 1/2

ii) S = ( 4, 6)

P(E) = 2/6 = 1/3

iii) S = ( 1, 2, 3, 4, 5, 6)

P(E) = 6/6 = 1

9) 36

10) 0, since there is no number '7' in a die

11) False. Maximum probability of an event is 1.

Here,

5/4 is 1.25 which is greater than 1

( Above attachment is regarding the 9th question)

Hoping everything is correct

All the best buddy