Physics, asked by shawbijay778, 9 months ago

7) Two equal Point Charges are
Placed in air
10 cm
the
a part and
force of interaction between
is 50mg - wt. Determine
magnitude of the charges
them
the​

Answers

Answered by Sumudawe
1

Answer:

Given, d=3m,f=0.19f

So, f=

r

2

kq

2

⇒kq

2

=0.19×9⇒q

2

=

9.0×10

9

1.71

Where k=9.0×10

9

⇒q=

0.19×10

−9

C

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