7) Two equal Point Charges are
Placed in air
10 cm
the
a part and
force of interaction between
is 50mg - wt. Determine
magnitude of the charges
them
the
Answers
Answered by
1
Answer:
Given, d=3m,f=0.19f
So, f=
r
2
kq
2
⇒kq
2
=0.19×9⇒q
2
=
9.0×10
9
1.71
Where k=9.0×10
9
⇒q=
0.19×10
−9
C
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