Question

7. Two numbers are in the ratio 10:13. If the difference between the numbers is 48, find the numbers.​

Answer 1

Answer:

$\boxed{\text{The numbers are 160 and 208}}$

Step-by-step explanation:

Two numbers are in the ratio 10:13

⇒ Let the numbers be '10a' and '13a'

the difference between the numbers is 48

⇒ 13a - 10a = 48

    3a = 48

    a = 48/3

    a = 16

→ 10a = 10(16) = 160

→ 13a = 13(16) = 208

$\textbf{The numbers are 160 and 208}$

Answer 2

Given:-

• Two numbers are in ratio 10:13.
• There difference is 48.

To find:-

• Numbers.

Solution:

Let the one number be 10x

And second number be 13x

So,

According to question

⇒13x - 10x = 48

⇒3x = 48

⇒x = 48/3

⇒x = 16

Verification:-

⇒13x - 10x = 48

• Put x = 16

⇒(13 × 16) - (10 × 16) = 48

⇒208 - 160 = 48

⇒48 = 48

Hence, Verified.

10x = 10 × 16 = 160

13x = 13 × 16 = 208.

Therefore,Numbers are 160 and 208.