Question

7. Two parallel chords of a circle of lengths 6 cm
and 8 cm lie on the opposite side of centre. If
distance between the chords is 7 cm, find the
radius of the circle.​

Answer 1

Answer:

Let AB and CD are two parallel chords of a circle having length 6 cm and 8 cm and radius is O.

Let the radius of the circle be r.

Now draw OP perpendicular to AB and OQ perpendicular to CD.

since OP is perpendicular to AB and OQ is perpendicular to CD and AB || CD

From figure, OP = 4 cm.

P, Q are the mid points of AB and CD respectively. [perpendicular from center bisects the chord]

So AP=PB=

2

AB

=

2

6

=3cm

CQ=QD=

2

CD

=

2

8

=4cm

Now in triangle OAP

OA

2

=OP

2

+AP

2

r

2

=16+9

r=

16+9

r=5cm

Step-by-step explanation:

hope it will help you