Question

7. Two wires of the same length and the same resistivity
are connected in parallel. Find the ratio of their areas of
cross section if the ratio of their electrical resistances
is 4:3​

Answer 1

1:4

The resistance of a wire of length l and cross section area A is given by,

R=ρ(l/A).

So

R2R1=l2l1A1A2=14.

Now current through a wire is   i ∝ 1/R.

∴i2i1 = R1R2 = 41

If their ends have the same potential differences then currents through them

will be in the ratio of 1:4.

Answer 2

Answer:

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