Question

7. Two years ago, a man was five times as old as his son. Two years later,
his
age will be 8 more than three times the age of the son. Find the
present ages of the man and his son.
​

Answer 1

Answer:

age of the Man is 15 and his son age is 8

Answer 2

Answer:

Step-by-step explanation:

Let's the present age of man=x

Let's the present age of his son=y

Two years ago,man was five times as old as his son=5(y-2)

x-2=5(y - 2)

x - 2=5y-10

x-5y-2+10=0

x-5y+8=0......equ(1)

Two years later the age of the man =x+2

Two years later the age of his son=y+2

Two years later the age of man will be 8 more than three times the age of his son=3(y+8)

x+2=3(y+8)

x+2=3y+24

x-3y+2-24=0

x - 3y -22.....equa(2)

equ(2)-equ(1)

x-3y-22=0

x-5y+8=0

________________

2y-30=0

2y=30

y=30/2=15

y value substitute in equation 1

x-5y+8=0

x-5×15+8=0

x-75+8=0

x - 67=0

x=67