Question

7. Using Cramer's rule, solve the given equations
x + y + z = 3, 2x + 3y + 4z = 9 and 4x – y +z = 4.​

Answer 1

$x = 1 \\ y = 1 \\ z = 1$

––––––––––

$x=3-2y$

$2\left(3-2y\right)+3y+4z=9 4\left(3-2y\right)-y+z=4$

$y=-3+4z z=-8+9y$

$z=-8+9\left(-3+4z\right)$

z=1

$y=-3+4\times 1$

y=1

$x=3-2$

x=1