Question

7. Walking 6/7th of his usual speed, a man is 12 minutes too late. What is the usual time taken by him to cover that distance?(Please answer with details)

Answer 1

Answer:

Let the distance be x

Let the original speed be y

Time originally taken = distance / speed

That means =x/y

Now the new speed is( 6/7)y

And new time is distance /new speed

X/ (6/7)y that can be written as 7x/6y

Now new time - original time = 12 min

7x/6y-x/y=12

After subtracting we get

X/y=12×6

X/y=72min