7) What is the effective resistance of two equal resistors connected in series?
➪Twice the resistance.
➪Half the resistance.
➪Same resistance.
➪None of the above.
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Side of square=15m
Length of rope=5m=radius
The area available for horse to graze is nothing but "Area of Quadrant of a circle'
∴ Area of Quadrant =4π×r2=43.14×5×5
=19.625m2
If the length of rope is increased to 10m then the new radius ,=10m
∴ Area of new quadrant =43.14×10×10
=78.5m2
∴ Increase in grazing area =78.5−19.625=58.875m2
Length of rope=5m=radius
The area available for horse to graze is nothing but "Area of Quadrant of a circle'
∴ Area of Quadrant =4π×r2=43.14×5×5
=19.625m2
If the length of rope is increased to 10m then the new radius ,=10m
∴ Area of new quadrant =43.14×10×10
=78.5m2
∴ Increase in grazing area =78.5−19.625=58.875m2
Are
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Side of square=15m
Length of rope=5m=radius
The area available for horse to graze is nothing but "Area of Quadrant of a circle'
∴ Area of Quadrant =4π×r2=43.14×5×5
=19.625m2
If the length of rope is increased to 10m then the new radius ,=10m
∴ Area of new quadrant =43.14×10×10
=78.5m2
∴ Increase in grazing area =78.5−19.625=58.875m2
Length of rope=5m=radius
The area available for horse to graze is nothing but "Area of Quadrant of a circle'
∴ Area of Quadrant =4π×r2=43.14×5×5
=19.625m2
If the length of rope is increased to 10m then the new radius ,=10m
∴ Area of new quadrant =43.14×10×10
=78.5m2
∴ Increase in grazing area =78.5−19.625=58.875m2
Answers
Answered by
7
Explanation:
The lengths of the sides of a triangle are in the ratio 3 : 4 : 5 and its perimeter is 144 cm. Let the sides be a = 3x , b = 4x and c = 5x . Hence, the area of the field is 864 cm².
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Answered by
4
Explanation:
Twice the resistance
R- R1 + R2
for series combination
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