Question

7.
What is the equivalent resistance of the following
network of resistances?
please reply fast ​

Answer 1

Answer:

last 2 resistors can be neglected since they are open.

Next 3 are in series so total 3ohm

which is parallel to 1 ohm

so Reff=3/4

Answer 2

Answer:

$\bold{ \frac{11}{4} \Omega}$

Explanation :

Here , 1Ω , 1Ω and 1Ω are in series combination .

For series combination , we use :

$\star \boxed{ \bold{ r_{eq}= r_1 + r_2 + r_3 + .....}}$

After solving this we get 3 Ω which is parallel combination with another 1Ω .

For parallel combination , we use :

$\star \boxed{ \bold{ \dfrac{1}{r_{eq}} = \dfrac{1}{r_1} + \dfrac{1}{r_2} + \dfrac{1}{r_3} + ...}}$

After solving , we get 3/4 Ω .

Now , all becomes in series combination and we get ,

11/4 Ω .

Solution refer to the attachment.