Question

7. What is the perimeter of a quadrilateral whose four sides measures 3whole1/6 cm, 2whole3/4 cm, 4whole5/12 cm and 2whole1/2 cm.​

Answer 1

Answer:

12 5/6 cm

Step-by-step explanation:

3 1/6 + 2 3/4 + 4 5/12 + 2 1/2 = 19/6 + 11/4 + 53/12 + 5/2

38/12 + 33/12 + 53/12 + 30/12 = 71/12 + 83/12 = 154/12 = 12 10/12 = 12 5/6

Answer 2

★ How to do :-

Here, we are given with the measurements of a quadrilateral. The measurements of all the four sides of the quadrilateral is given to us. The given measurements are in the form of the mixed fraction. In mixed fractions, we will have one whole number and a proper fraction. So, first we should convert them into improper fractions, which has the numerator greater than the denominator. After, converting to that we should convert the unlike fractions to like fractions by the method of LCM of denominators. Then, we can add all the fractions so that we can get the perimeter. So, let's solve!!

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➤ Solution :-

${\sf \longrightarrow \underline{\boxed{\sf Perimetre = Sum \: of \: all \: sides}}}$

Substitute the values to all sides.

${\tt \leadsto 3 \dfrac{1}{6} + 2 \dfrac{3}{4} + 4 \dfrac{5}{12} + 2 \dfrac{1}{2}}$

Convert all mixed fractions to improper fractions.

${\tt \leadsto \dfrac{19}{6} + \dfrac{11}{4} + \dfrac{53}{12} + \dfrac{5}{2}}$

LCM of 6, 4, 12 and 2 is 12.

${\tt \leadsto \dfrac{19 \times 2}{6 \times 2} + \dfrac{11 \times 3}{4 \times 3} + \dfrac{53}{12} + \dfrac{5 \times 6}{2 \times 6}}$

Multiply the numerators and denominators of all fractions.

${\tt \leadsto \dfrac{38}{12} + \dfrac{33}{12} + \dfrac{53}{12} + \dfrac{30}{12}}$

Write all numerators with a common denominator.

${\tt \leadsto \dfrac{38 + 33 + 53 + 30}{12}}$

Add all fractions and write it in simplest form.

${\tt \leadsto \cancel \dfrac{154}{12} = \dfrac{77}{6}}$

Write the obtained answer in the form of mixed fraction.

${\tt \leadsto \dfrac{77}{6} = 12 \dfrac{5}{6}}$

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${\red{\underline{\boxed{\bf \small{So, \: the \: perimeter \: of \: the \: quadrilateral \: is \: 12 \dfrac{5}{6} \: cm.}}}}}$