Question

7. What is the smallest 6 digit number that is exactly
divisible by 48 and 108



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Answer 1

First, we find the LCM of 48 and 108 = 432

the smallest six digit number = 100000

100000÷432 =

quotient = 231

remainder = 208

the required number = 100000 - remainder + LCM = 100000 - 208 + 432 = 100224.

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Answer 2

Answer:

first we find LCM of 48 and 108 = 432

the smallest 6 digit number = 100000

100000 divide 432=

quotient = 231

remainder= 208

the required number= 100000

remainder+LCM+100000-208+432= 100224

Step-by-step explanation:

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