Question

7. What must be subtracted from 3a2 - 5ab - 262 – 3 to get 5a2 – 7ab – 3b2 + 3a?
8. The perimeter of a triangle is 7p2 - 5p + 11 and two of its sides are p2 + 2p – 1 and
3p2 - 6p + 3. Find the third side of the triangle.​

Answer 1

Answer:

ANSWER

From the question, its understood that we have to subtract 5a

2

−7ab−3b

2

+3a from 3a

2

−5ab−2b

2

−3

= 3a

2

−5ab−2b

2

−3−(5a

2

−7ab−3b

2

+3a)

= 3a

2

−5ab−2b

2

−3−5a

2

+7ab+3b

2

−3a

= −2a

2

+2ab+b

2

−3a−3

Answer 2

Answer:

1@2@3@4@5@6@7@8@9@0@10@