Question

7. What must be subtracted from
52 - 16ab - 362 - 1to get 64 - 3ab - 40 + 1?​

Answer 1

Let us take an example :

What must be subtracted from 10 to get 4, the answer is 6. How did we do that ?

Simply by subtracting 4 from 10.

Similarly we'll proceed in this question.

= ( 52 – 16ab – 362 – 1 ) – ( 64 – 3ab – 40 + 1 )

= ( – 311 – 16ab ) – ( 25 – 3ab )

= – 311 – 16ab – 25 + 3ab

= – 336 – 13ab

So, – 336 – 13ab should be subtracted from the number.

Answer 2

Hi,friend

Your answer is -12-13ab-322-2.

Full solution is given below...

Let suppose the Polynomial be x.

or,52-16ab-362-1-x=64-3ab-40+1

or,(52-16ab-362-1)-(64-3ab-40+1)=x

or,52-16ab-362-1-64+3ab+40-1=x

or,x=-12-13ab-322-2...

Hope it helps you a lot