Question

7. When a car driver travelling at a speed of 10 m/s applies brakes and brings the car to rest in 20 s, then the retardation will be:
(a) + 2 m/s^2
(b) − 2 m/s^2
(c) − 0.5 m/s^2
(d) + 0.5 m/s^2

Answer 1

Answer:

Answer: 0.5 m/s2

U (initial velocity) = 10 m/s

V (final velocity) = 0 m/s

t (time taken) = 20s

a (acceleration) = (V – U) / t

a = 0 – 10 / 20

a = – 0.5 m/s2

Retardation = 0.5 m/s2

Explanation: