Question

7. When the repeating decimal 0.3636...... is written in simplest fractional form p/q, find value of
P+6q​

Answer 1

Answer:

let x=0.363636...... this is equation 1

multiplying equation 1 with 100

100x=36.3636........... this equation 2

so subtract equ1 from equ2

100x-x= 36.3636......-.363636.....

99x=36

x=36/99

x=12/33

x=4/11

so p=4,q=11

p+6q= 4+66

=70

Answer 2

Step-by-step explanation:

Let, x = 0.3636.... ----(1)

On multiplying equation (1) by 100, we get

100x = 36.3636.... ----(2)

Subtracting eqn (1) from eqn (2), we get

100x-x = 36.3636....-0.3636....

99x = 36

Therefore, x = 4/11 = p/q

On comparing, p = 4

q = 11

Therefore, p+6q = 4+66

= 70

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