Question

7. Write a Pythagorean triplet whose members are formed by the given natural numbers.
( (a) 6 b) 14​

Answer 1

Answer:

a)6,8and 10=m=3,2m=6,mSQ-1=8,mSQ+1=10

b)14,48, and 50=m=7,2m=14,mSQ-1=48,mSQ+1=50

Step-by-step explanation:

a)As we know 2m, mSQ

+1 and mSQ−1 from a Pythagorean triplet for any number , m>1

Let us assume 2m=6

Therefore, m =3

mSQ-1=3*3-1=8

mSQ+1=3*3+1=10

Hence the triplet is 6,8, and 10 Answer

b)As we know 2m, mSQ+1 and mSQ−1 from a Pythagorean triplet for any number , m>1

Let us assume 2m=14

Therefore, m =7

mSQ-1=7*7-1=48

mSQ+1=7*7+1=50

Hence the triplet is 14,48, and 50 Answer