7. Write values in standard and scientific notation a) The radius of 1" orbit of Hydrogen atom is r= 0.53 A°=
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If the radius of the first orbit of hydrogen atom is 0.53A
∘
, then the de-Broglie wavelength of the electron in the ground state of hydrogen atom will be :
Medium
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Correct option is
B
3.33A
∘
According to Bohr's quantization condition
mvr=
2π
nh
∴
mv
h
=
n
2πr
....(i)
∵ de-Broglie wavelength of a particle
λ=
mv
h
....(ii)
From Eqs. (i) and (ii),
λ=
n
2πr
∵ Electron in ground state
r=0.53A
∘
and n=1
⇒λ=
1
2π×0.53A
∘
=3.33A
∘
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3.338 is your answer
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