Question

(7 x-1)(4-1/3(2 x-(1- x) /2=10/3<br />please answer my question​

Answer 1

Answer:

(7x-1)/4 – 1/3(2x – (1-x)/2) = 10/3 Upon expansion (7x-1)/4 – (4x-1+x)/6 = 10/3 (7x-1)/4 – (5x-1)/6 = 10/3 By taking LCM for 4 and 6 is 24 ((7x-1)6 – (5x-1)4)/24 = 10/3 (42x – 6 – 20x + 4)/24 = 10/3 (22x – 2)/24 = 10/3 By cross-multiplying 22x – 2 = 10(8) 22x – 2 = 80 22x = 80+2 22x = 82 x = 82/22 = 41/11 Let us verify the given equation now, (7x-1)/4 – 1/3(2x – (1-x)/2) = 10/3 By substituting the value of ‘x’ we get, (7x-1)/4 – (5x-1)/6 = 10/3 (7(41/11)-1)/4 – (5(41/11)-1)/6 = 10/3 (287/11 – 1)/4 – (205/11 – 1)/6 = 10/3 (287-11)/44 – (205-11)/66 = 10/3 276/44 – 194/66 = 10/3 69/11 – 97/33 = 10/3 ((69×3) – (97×1))/33 = 10/3 (207 – 97)/33 = 10/3 110/33 = 10/3 10/3 = 10/3