Question

7(x + 2a)2 + 3a2 = 5a (7x + 23a)
solve by completing squares
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Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

           7*(x+2*a)^2+3*a^2-(5*a*(7*x+23*a))=0 

STEP1:Equation at the end of step 1

((7•((x+2a)2))+(3•(a2)))-5a•(7x+23a) = 0

STEP 2 :

Equation at the end of step2:

((7•((x+2a)2))+3a2)-5a•(7x+23a) = 0

STEP3:Equation at the end of step 3

(7 • (x + 2a)2 + 3a2) - 5a • (7x + 23a) = 0

STEP4:

STEP5:Pulling out like terms

 5.1     Pull out like factors :

   7x2 - 7xa - 84a2  =   7 • (x2 - xa - 12a2) 

Trying to factor a multi variable polynomial :

 5.2    Factoring    x2 - xa - 12a2 

Try to factor this multi-variable trinomial using trial and error 

 Found a factorization  :  (x + 3a)•(x - 4a)

Equation at the end of step5:

7 • (x + 3a) • (x - 4a) = 0