Math, asked by shibamsen2006, 4 hours ago

(7/x-3xy)^3
please answer it fast​

Answers

Answered by krishnakant673558
0

Hope it helps you please support me

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Answered by sg693363
0

Answer:

Step-by-step explanation:

(\frac{7}{x} -3xy)^{3} \\\\Using identity :[ (a-b)^{3} =a^{3} -b^{3} -3ab(a-b)]\\\\(\frac{7}{x} )^{3} -(3xy)^{3} -3(\frac{7}{x} )(3xy)(\frac{7}{x} -3xy)\\\\\frac{343}{x^{3} } -27x^{3} y^{3} -63y(\frac{7-3x^{2} y}{x} )\\\\\frac{343}{x^{3} } -27x^{3} y^{3} -\frac{441y+189x^{2} y^{2}}{x}   )\\\\\frac{343-27x^{6}y^{3}-441yx^{2} +189x^{4} y^{2}   }{x^{3} }

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