Math, asked by shivarajghevare, 1 month ago

7^x × 9^y × 4^z = 14^4 × 6^8 find value of z​

Answers

Answered by suraniparul19
0

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Answered by anbuvettri100a
0

Answer:

z = 6

Step-by-step explanation:

7^x * 9^y * 4^z = 14^4 * 6^8

we can write:

14 as 7*2

6 as 2*3

so,

14^4 = 7^4*2^4

6^8 = 2^8*3^8 hence,

7^x * 9^y * 4^z = 7^4 * 2^4 * 2^8 * 3^8 use laws of exponents

7^x * 9^y * 4^z = 7^4 * 2^12 * 3^8

Since, 2 = 4^1/2 and 3 = 9^1/2

2^12 = 4^6

3^8 = 9^4

Write these in the expression

7^x * 9^y * 4^z = 7^4 * 9^4 * 4^6

7^x = 7^4

x = 4

9^y = 9^4

y = 4

4^z = 4^6

z = 6

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