Question

7 x minus 1 upon 4 minus 1 upon 3 (2 X + X - 1) upon 2 is equal to to 6 1 upon 3

Answer 1

SOLUTION

TO SOLVE

$\displaystyle\sf{ \frac{7x - 1}{4} - \frac{1}{3} \bigg(2x + \frac{x - 1}{2} \bigg) = 6 \frac{1}{3} }$

EVALUATION

Here the given expression is

$\displaystyle\sf{ \frac{7x - 1}{4} - \frac{1}{3} \bigg(2x + \frac{x - 1}{2} \bigg) = 6 \frac{1}{3} }$

We solve for x as below

$\displaystyle\sf{ \frac{7x - 1}{4} - \frac{1}{3} \bigg(2x + \frac{x - 1}{2} \bigg) = 6 \frac{1}{3} }$

$\displaystyle\sf{ \implies \: \frac{7x - 1}{4} - \frac{1}{3} \bigg( \frac{4x + x - 1}{2} \bigg) = 6 \frac{1}{3} }$

$\displaystyle\sf{ \implies \: \frac{7x - 1}{4} - \frac{1}{3} \bigg( \frac{5 x - 1}{2} \bigg) = \frac{19}{3} }$

$\displaystyle\sf{ \implies \: \frac{21x - 3 - 10x + 2}{12} = \frac{19}{3} }$

$\displaystyle\sf{ \implies \: \frac{11x - 1}{12} = \frac{19}{3} }$

$\displaystyle\sf{ \implies \: 11x - 1= \frac{19}{3} \times 12 }$

$\displaystyle\sf{ \implies \: 11x - 1= 76 }$

$\displaystyle\sf{ \implies \: 11x = 76 + 1 }$

$\displaystyle\sf{ \implies \: 11x = 77 }$

$\displaystyle\sf{ \implies \: x = 7 }$

FINAL ANSWER

Hence the required solution is x = 7

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Answer 2

⟹

4

7x−1

−

3

1

(

2

4x+x−1

)=6

3

1

\displaystyle\sf{ \implies \: \frac{7x - 1}{4} - \frac{1}{3} \bigg( \frac{5 x - 1}{2} \bigg) = \frac{19}{3} }⟹

4

7x−1

−

3

1

(

2

5x−1

)=

3

19

\displaystyle\sf{ \implies \: \frac{21x - 3 - 10x + 2}{12} = \frac{19}{3} }⟹

12

21x−3−10x+2

=

3

19

\displaystyle\sf{ \implies \: \frac{11x - 1}{12} = \frac{19}{3} }⟹

12

11x−1

=

3

19

\displaystyle\sf{ \implies \: 11x - 1= \frac{19}{3} \times 12 }⟹11x−1=

3

19

×12

\displaystyle\sf{ \implies \: 11x - 1= 76 }⟹11x−1=76

\displaystyle\sf{ \implies \: 11x = 76 + 1 }⟹11x=76+1

\displaystyle\sf{ \implies \: 11x = 77 }⟹11x=77

\displaystyle\sf{ \implies \: x = 7 }⟹x=7

FINAL ANSWER

Hence the required solution is x = 7