7^x-y=49 and 7^x+y = 343 then find x,y
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Answered by
2
Step-by-step explanation:
Suppose,
x = 5/2 & y = 1/2
Now, solve both
1. 7^5/2+1/2=343
7^5+1/2=343
7^3= 343
343= 343
2. 7^5/2-1/2 = 49
7^ 5-1/2= 49
7^2=49
49= 49
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Answered by
2
Step-by-step explanation:
7^x-y= 49
7^x-y= 7^2
since the base of LHS and RHS are same, we can equate the power of both sides
x-y=2
similarly you will get
x+y= 3
solving 1 & 2 you'll get
2x= 5
x=5/2 or 2.5
substitute x in eqn 1
x-y=2
5/2-y=2
y=5/2+2
y=9/2 or 4.5
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